Write a program to find the reverse of a number ? | Shell Program|

#!/bin/bash
echo "Enter the number:"
read n
sd=0
rev=0
g=$n
while [ $n -gt 0 ]
do
sd=$(($n%10))
rev=$(($rev*10+$sd))
n=$(($n/10))
done
echo "Reverse of $g is:$rev"

OUTPUT

Enter the number:
1234
Reverse of 1234 is:4321